LOOKING TO ADVANCE YOUR ORACLE CAREER? TRY ORACLE 1Z0-106 EXAM QUESTIONS

Looking to Advance Your Oracle Career? Try Oracle 1Z0-106 Exam Questions

Looking to Advance Your Oracle Career? Try Oracle 1Z0-106 Exam Questions

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Oracle 1Z0-106 certification exam consists of 80 multiple-choice questions that must be completed within 120 minutes. 1Z0-106 exam covers a wide range of topics, including installation and configuration of Oracle Linux 8, management of users and groups, file systems and storage, advanced networking concepts, system security, and troubleshooting techniques. Candidates must demonstrate a deep understanding of these topics to pass the exam.

Oracle Linux 8 Advanced System Administration exam is intended for IT professionals who have experience working with Linux systems and are looking to advance their career in system administration. 1Z0-106 exam is ideal for system administrators, network administrators, and IT professionals who are responsible for managing and administering Oracle Linux 8 systems. Oracle Linux 8 Advanced System Administration certification is also recommended for those who are looking to specialize in Oracle Linux 8 system administration.

Oracle 1Z0-106 Certification Exam is a valuable asset for IT professionals who manage enterprise-level systems running on Oracle Linux 8 operating system. Oracle Linux 8 Advanced System Administration certification provides demonstration of knowledge and skill in advanced system administration tasks, improving IT professionals' career opportunities and increasing value for enterprises that utilize Linux OS. Oracle Linux 8 Advanced System Administration certification offers IT professionals the opportunity to distinguish themselves within the field of Linux system management and gain a competitive edge in the job market.

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Oracle Linux 8 Advanced System Administration Sample Questions (Q50-Q55):

NEW QUESTION # 50
Which two are true about using Ksplice?

  • A. Ksplice can be used without a network connection
  • B. Yum cannot upgrade a kernel patched by Ksplice
  • C. It can patch the kernel without shutting down the system.
  • D. The Ksplice client is freely available to all customers.
  • E. Ksplice has two clients; each can run in three different modes.

Answer: B,C


NEW QUESTION # 51
Examine this command, which executes successfully:
# nmcli con add con-name eth2 type ethernet ifname eth2 Ipv6.address 2804:14c:110:ab2f:c3lb:1212:7917:708a/64 Ipv6.gateway 2804:14c:110:ab2f::1003 Ipv4.address 192.168.0.5/24 ipv4.gateway 192.168.0.254 The eth2 connection does not exist. Which two statements are true?

  • A. A static IP address is assigned to the eth2 connection
  • B. It configures an automatic IPV6 address.
  • C. Ethernet connection eth2 is created.
  • D. The configuration is saved in /etc/sysconfig/network.

Answer: A,C


NEW QUESTION # 52
Which command produces human-readable timestamps in kernel ring buffer messages?

  • A. dmesg -t
  • B. dmesg -x
  • C. dmesg -T
  • D. dmesg -W

Answer: C

Explanation:
* Option C (Correct):Thedmesg -Tcommand converts the timestamps in the kernel ring buffer messages to a human-readable format. The defaultdmesgoutput shows the timestamps in a raw format (seconds since the kernel started), while the-Toption translates these timestamps into a human-readable date and time.
* Option A (Incorrect):The-toption is used to remove the timestamps entirely from the output.
* Option B (Incorrect):The-xoption provides extended information about the message (e.g., facility, level).
* Option D (Incorrect):The-Woption waits for new messages and does not convert timestamps to a human-readable format.
Oracle Linux Reference:Refer to:
* man dmesgfor more details ondmesgoptions.


NEW QUESTION # 53
Examine /etc/anacrontab:
SHELL=/bin/sh
PATH=/sbin:/bin:/usr/sbin:/usr/bin
MAILTO=root
# the maximal random delay added to the base delay of the jobs
RANDOM_DELAY=45
# the jobs are started during the following hours only
START_HOURS_RANGE=3-22
# period in days delay in minutes job-identifier command
1 5 dailyjob nice run-parts /etc/cron.daily
7 25 weeklyjob nice run-parts /etc/cron.weekly
@monthly 45 monthlyjob nice run-parts /etc/cron.monthly
Which two statements are true about the jobs scheduled in this file?

  • A. Scripts run by the third job are delayed between 45 and 90 minutes.
  • B. Scripts run by the first job are delayed between 11 and 45 minutes.
  • C. Scripts run by the second job are delayed between 31 and 70 minutes.
  • D. Jobs defined in this anacrontab file are randomly delayed by up to 51 minutes.
  • E. Jobs defined in this anacrontab file can be executed between 15:00 and 22:00

Answer: A,E

Explanation:
Understanding the anacrontab Entries:
The /etc/anacrontab file contains the following variables and job definitions:
SHELL=/bin/sh
PATH=/sbin:/bin:/usr/sbin:/usr/bin
MAILTO=root
# the maximal random delay added to the base delay of the jobs
RANDOM_DELAY=45
# the jobs are started during the following hours only
START_HOURS_RANGE=3-22
# period in days delay in minutes job-identifier command
1 5 dailyjob nice run-parts /etc/cron.daily
7 25 weeklyjob nice run-parts /etc/cron.weekly
@monthly 45 monthlyjob nice run-parts /etc/cron.monthly
Variables Explained:
* RANDOM_DELAY=45
* Specifies that arandom delaybetween 0 and 45 minutes is added to the base delay of each job.
* START_HOURS_RANGE=3-22
* Jobs are allowed to start only between03:00 (3 AM)and22:00 (10 PM).
Job Delays Calculated:
* First Job (dailyjob):
* Base Delay:5 minutes
* Random Delay:0 to 45 minutes
* Total Delay:5 + (0 to 45) =5 to 50 minutes
* Second Job (weeklyjob):
* Base Delay:25 minutes
* Random Delay:0 to 45 minutes
* Total Delay:25 + (0 to 45) =25 to 70 minutes
* Third Job (monthlyjob):
* Base Delay:45 minutes
* Random Delay:0 to 45 minutes
* Total Delay:45 + (0 to 45) =45 to 90 minutes
Option B: Jobs defined in this anacrontab file can be executed between 15:00 and 22:00
* Explanation:
* The START_HOURS_RANGE=3-22 setting allows jobs to start between03:00 and 22:00.
* Therefore, it's true that jobscan be executed between 15:00 (3 PM) and 22:00 (10 PM).
* This statement is correct because the specified time range falls within the allowed start hours.
* Oracle Linux Reference:
* OracleLinux 8: Scheduling Tasks- Section on "Anacron Configuration Files":
"The START_HOURS_RANGE variable defines the time window during which Anacron jobs can run." Option C: Scripts run by the third job are delayed between 45 and 90 minutes.
* Explanation:
* The third job (monthlyjob) has abase delay of 45 minutes.
* With a RANDOM_DELAY of up to 45 minutes, thetotal delaybefore execution is between45 and 90 minutes.
* Therefore, this statement is accurate.
* Oracle Linux Reference:
* OracleLinux 8: Scheduling Tasks- Section on "Understanding Anacron Job Delays":
"Each job's delay is calculated by adding its defined delay to a random value between 0 and RANDOM_DELAY." Why Other Options Are Not Correct:
* Option A:Scripts run by the first job are delayed between 11 and 45 minutes.
* Explanation:
* The first job (dailyjob) has a total delay between5 and 50 minutes(5-minute base delay plus up to 45 minutes random delay).
* Therefore, the statement specifying11 to 45 minutesis incorrect.
* Option D:Jobs defined in this anacrontab file are randomly delayed by up to 51 minutes.
* Explanation:
* The maximum random delay is set by RANDOM_DELAY=45, so the random delay is up to45 minutes, not 51.
* Therefore, this statement is false.
* Option E:Scripts run by the second job are delayed between 31 and 70 minutes.
* Explanation:
* The second job (weeklyjob) has a total delay between25 and 70 minutes(25-minute base delay plus up to 45 minutes random delay).
* The statement specifies a delay between31 and 70 minutes, which is incorrect because the minimum delay is 25 minutes.
Conclusion:
Options B and C are correct based on the configuration specified in /etc/anacrontab. They accurately reflect the possible execution times and delays for the jobs defined.


NEW QUESTION # 54
Examine this command:
# auditctl -w /etc/passwd -p w -k pass
Which two statements are true upon execution?

  • A. A write occurs to /etc/audit/rules.d/audit.rules.
  • B. An audit is defined that creates a log entry every time a write occurs to /etc/passwd.
  • C. A write occurs to /etc/audit/audit.rules.
  • D. An audit rule is defined that creates a log entry every time /etc/passwd is read.
  • E. An audit rule is defined with the keyword pass.

Answer: B,E


NEW QUESTION # 55
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